Question

ABCD is a parallelogram find Angle B if Angle A = 3 X - 20 and angle C = X + 50​

Answer 1

Given:-

Angle A = 3 X - 20 and angle C = X + 50

To find:-

Angle B

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∠A = ∠C (Opposite angles of a parallelogram are equal)

3x - 50 = x + 40

3x - x = 40 + 50

2x = 90

x = \frac{90}{2}

x = 45°

So the value of x is 45°.

• Hence, Angle B = 45°

Answer 2

Angle A = 3 X - 20 and angle C = X + 50

To find:-

Angle B

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∠A = ∠C (Opposite angles of a parallelogram are equal)

3x - 50 = x + 40

3x - x = 40 + 50

2x = 90

x = \frac{90}{2}

x = 45°