Question

ABCD is a parallelogram find the angles if one angle is 2x+30 second angle is 2y+5 and third angle is 3x+15​

Answer 1

Answer:

Step-by-step explanation:

let <A be(2x+30),<B be (2y+5) and <C be (3x+15)

so <A=<C {opposite angles are equal in a parallelogram}

2x+30=3x+15

x=15

2x+30=2×15+30

         =60°

<C=60°

60+60=120

so <B+<D=360-120=240

<B=<D{opposite angles are equal in a parallelogram}

240/2=120

so <D is 120 °

hope it helps