Question

ABCD is a parallelogram.find the value of x,y and z. AB=2X-1 and DC=X+5.Diagnonal AC produced to E angel dac=65° angel cab=y angel dce=z find the value of x, y and z​

Answer 1

From the figure 

AD∥BC,BD is the transversal line 

⟹∠ADB=∠DBC     (∵alternate angles)

⟹z=30∘

Also

100∘,x are supplementary angles 

So x=180∘−100∘=80∘

x,y,30∘ forms a triangle 

⟹x+y+30∘=180∘

⟹y=180∘−80∘−30∘=70∘

Answer 2

Step-by-step explanation:

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘