ABCD is a parallelogram. Find x, y and z
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Answered by
14
hello friend!
here is ur answer!
according to the figure ∠DAE = 125° AND ∠ECB =56°
Now,
X= 180°-125° = 75°
Y = 125°-56° = 69°
z = 360°- (x+y+125°)
= 360° - 269°
= 91°
hope it helps uh!!!
here is ur answer!
according to the figure ∠DAE = 125° AND ∠ECB =56°
Now,
X= 180°-125° = 75°
Y = 125°-56° = 69°
z = 360°- (x+y+125°)
= 360° - 269°
= 91°
hope it helps uh!!!
aryan04kaushik:
x = 180 - 125 which is 55
Answered by
15
In the given figure,
∠A=125
∠BCE =56
x + ∠A=180 . . . . . . (Interior angles on the same side of transversal are supplementary)
x + 125=180
x =180-125
x = 55°
∠A = ∠C . . . . . (opposite angles are equal)
∠C = 125°
∠BCE + ∠Y = ∠C
56 + Y = 125
Y = 125 - 56
Y = 69°
∠Y + ∠Z = 180° ( Interior angles on the same side of transversal are supplementary)
69° + ∠Z = 180°
∠Z = 180 - 69
∠Z = 111°
∠A=125
∠BCE =56
x + ∠A=180 . . . . . . (Interior angles on the same side of transversal are supplementary)
x + 125=180
x =180-125
x = 55°
∠A = ∠C . . . . . (opposite angles are equal)
∠C = 125°
∠BCE + ∠Y = ∠C
56 + Y = 125
Y = 125 - 56
Y = 69°
∠Y + ∠Z = 180° ( Interior angles on the same side of transversal are supplementary)
69° + ∠Z = 180°
∠Z = 180 - 69
∠Z = 111°
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