ABCD is a parallelogram. If AB = 200 cm, AD = 130 cm and area of the parallelogram is 2.4 sq. m, calculate :- AE and EB
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Area of parralelogram = base × height
Area of parralelogram ABCD = 25 × DE
200 = 25 × DE
DE = 8 cm
Applying pythagoras theorem in triangle ADE
Hypontenuse² = Base² + Perpendicular ²
17² = 8² + AE²
289 = 64 + AE²
AE² = 289 - 64 = 225
AE = √225 = 15 cm
EB = AB - AE = 25 - 15 = 10 cm.
Step-by-step explanation:
may this helps u
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