Abcd is a parallelogram. If area of abl is 15 cm2 and area of dcl is 32 cm2, find the area of the parallelogram abcd
Answers
Given : Abcd is a parallelogram.
area of abl is 15 cm²
area of dcl is 32 cm²
To Find : area of the parallelogram abcd
Solution:
area of abl is 15 cm²
Perpendicular distance of l from ab = x cm
=> (1/2) ab * x = 15
=> x = 30/ab cm
area of dcl is 32 cm²
Perpendicular distance of l from cd = y
=> (1/2) cd * y = 32
=> y = 64/cd cm
as ab || cd ( opposite sides of parallelogram)
x + y = h ( distance between ab and cd )
ab = cd
h = 30/ab + 64/cd
=> h = 30/ab + 64/ab
=> h = 94/ab cm
Area of parallelogram abcd = ab * h
= ab * 94/ab
= 94 cm²
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Answer:
Given : Abcd is a parallelogram.
area of abl is 15 cm²
area of dcl is 32 cm²
To Find : area of the parallelogram abcd
Solution:
area of abl is 15 cm²
Perpendicular distance of l from ab = x cm
=> (1/2) ab * x = 15
=> x = 30/ab cm
area of dcl is 32 cm²
Perpendicular distance of l from cd = y
=> (1/2) cd * y = 32
=> y = 64/cd cm
as ab || cd ( opposite sides of parallelogram)
x + y = h ( distance between ab and cd )
ab = cd
h = 30/ab + 64/cd
=> h = 30/ab + 64/ab
=> h = 94/ab cm
Area of parallelogram abcd = ab * h
= ab * 94/ab
= 94 cm²