ABCD is a parallelogram. If the two diagonals are equal, find the measure of ∠ABC.
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Since ABCD is a parallelogram. Therefore,
AD=BC
AB= CD
Thus, in △s ABD and ACB,
AD= BC
BD= AC
AB= AB
So, by SSS criterion of congruence,
△ABD≅ △ACB
Therefore,
∠BAD=∠ABC
Now,
AD∥BC
and transversal AB intersects them at A and B respectively.
Therefore,
∠BAD+ ∠ABC= 180
o
∠ABC+ ∠ABC= 180
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2∠ABC= 180
o
∠ABC= 90
o
Hence, the measure of ∠ABC is 90
o
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