Question

ABCD is a parallelogram. If their diagonals at O. AO=9 cm, OB = x-y, OC= x+y, OD= 5cm. Find the value of x and y.

Answer 1

we know that,diagonal bisect each other at 90° in parallelogram.

so, 5= x-y.........(i)

similarly,, 9= x+y......(ii)

adding equation (i) and(ii)

5+9= x+y+x-y

14= 2x

so,,x=7

putting the value of x in eq. (ii)

9=7+y

y=2

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that $ABCD$ is a parallelogram. If their diagonals at $O$. $AO=9$ cm, $OB = x-y$, $OC= x+y$, $OD= 5$ cm.

To Find:-

We have to find that the value of $x$ and $y$.

Solution:-

According to the problem

Since diagonals of a parallelogram bisect each other.

$x+y=9 -(i)$   and  $x-y=5 -(ii)$

solving both we get

$2x=14\\\Rightarrow x=7cm$  and $7-y=5$

$y=2$cm

∴$x=7$cm  and $y=2$cm

Final Answer:-

The correct answer is the value of $x$ and $y$ are $7cm$ and $2$ cm respectively.

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