Question

ABCD is a parallelogram .in this AB,CD are parallel and also AD,BC also parallel .angle A =65° calculate B,C,D angles​

Answer 1

Step-by-step explanation:

Given <B = 75° and <A = 32°

From triangle BCE, <BCE = 180-(75+90) =15°

From triangle AFD, <ADF = 180-(90+32) = 58°

Also <ECD=<FDC=90° (as CD and AB are parallel)

So for trapezoid ABCD,

<BCD = <BCE + <ECD = 15+90 =105°

<ADC = <ADF + <FDC = 58+90 = 148°

So <C = 105° and <D =148°

Answer 2

Answer:

this is your answer

Step-by-step explanation:

hope it helps you