Question

ABCD is a parallelogram in which√a = 110°​

Answer 1

Step-by-step explanation:

Given ∠A = 110°

But we know that sum of adjacent angles of a parallelogram is 180°

∠A + ∠B = 180°

110o+ ∠B = 180°

∠B = 180°– 110°= 70°

Also ∠B + ∠C = 180° [Since ∠B and ∠C are adjacent angles]

70o+ ∠C = 180°

∠C = 180°– 70o= 110°

Now ∠C + ∠D = 180°[Since ∠C and ∠D are adjacent angles]

110°+ ∠D = 180°

∠D = 180o– 110°= 70

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