ABCD is a parallelogram in which√a = 110°
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Step-by-step explanation:
Given ∠A = 110°
But we know that sum of adjacent angles of a parallelogram is 180°
∠A + ∠B = 180°
110o+ ∠B = 180°
∠B = 180°– 110°= 70°
Also ∠B + ∠C = 180° [Since ∠B and ∠C are adjacent angles]
70o+ ∠C = 180°
∠C = 180°– 70o= 110°
Now ∠C + ∠D = 180°[Since ∠C and ∠D are adjacent angles]
110°+ ∠D = 180°
∠D = 180o– 110°= 70
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