Math, asked by Nirbikh, 7 months ago

ABCD is a parallelogram in which ∠A= (3x - 4)° and ∠B= (3x + 10)°. Find the measure of ∠A.​

Answers

Answered by utsav96
0
Pls mark as brainliest answer
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Answered by vedanshaggarwal2006
0

Answer:

∠A + ∠B = 180° (Adjacent angles of parallelogram are supplementary)

(3x - 4)° + (3x + 10)° = 180°

3x - 4 + 3x + 10 = 180°

6x + 6 = 180°

6x = 180 - 6

6x = 174

x = \frac{174}{6}

x = 29°

∠A = 3 × 29 - 4 = 83°

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