ABCD is a parallelogram in which am and cm are perpendicular from vertices a and c respectively on the diagonal BD show that 1) triangle amb is congurent to triangle cnd 2) am=cn
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In triangles AMD and CNB
AD=BC(opposite sides of a parallelogram)
∠AMB=∠CNB=90
∘
∠ADM=∠NBC since AD∥BC and BD is the transversal.
So, △AMD≅△CNB by AAS
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