ABCD is a parallelogram in which angle A = 110 degree. Find the measure of each of the angles angle B angle C and angle D.
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Step-by-step explanation:
Given ∠A = 110o But we know that sum of adjacent angles of a parallelogram is 180o ∠A + ∠B = 180o 110o+ ∠B = 180o ∠B = 180o– 110o= 70o. Also ∠B + ∠C = 180o [Since ∠B and ∠C are adjacent angles] 70o+ ∠C = 180o ∠C = 180o– 70o= 110o. Now ∠C + ∠D = 180o [Since ∠C and ∠D are adjacent angles] 110o+ ∠D = 180o ∠D = 180o– 110o= 70o
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Answer:
A+B= 180°(adjacent angles of a paralellogram are equal
B=180°-110°
B=70°
A=C=110°( opposite angles of a parallelogram are equal)
B=D=70°(opposite angles of a parallelogram are equal)
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