Math, asked by siddhantsingh, 1 year ago

ABCD is a parallelogram in which angle A is equal to 110 degree find the measure of each of the angles Angle B and angle C and angle d

Answers

Answered by mysticd
200

Answer:

In a parallelogram ABCD,

\angle A=\angle C = 110

and

\angle B=\angle D = 70

Step-by-step explanation:

Given ABCD is a parallelogram.

and

\angle A =110-----(1)

i ) We know that,

/* Sum of adjacent angles are supplementary in a parallelogram */

\angle A+ \angle B = 180

\implies110+\angle B = 180

\implies \angle B = 180-110

\implies \angle B = 70° ---(2)

/* In a parallelogram ,

Opposite angles are equal */

Therefore,

In a parallelogram ABCD ,

\angle A=\angle C = 110

and

\angle B=\angle D = 70

••••

Answered by MsBombshell
73

ĂŃŚŴĔŔ

∠A =  ∠C (opposite angles of a parallelogram are equal)

So,  ∠C = 110°  (as ∠A = 110°)

Adjacent angles of a parallelogram are supplementary. So,

∠A + ∠B = 180° ⇒ ∠B = 180° - 110° = 70°

Again, opposite angles of a parallelogram are equal. So, ∠B = ∠D = 70°.

Thus, ∠A = ∠C = 110° and ∠B = ∠D = 70°.

Be brainly♡~

❤Inshaan69❤

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