ABCD is a parallelogram in which angle DAB = 65 degree and angle CBD = 50 degree. Find the measure of angle CDB and angle ADB
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Answer:
ABCD Is a parallelogram
in Parallelogram opposite angles are equal
& sum of adjacent angle = 180°
∠DAB = 65° => ∠DCB = 65°
∠CBD = 50°
∠CDB = ?
∠CDB + ∠CBD + ∠DCB = 180° ( sum of angles of triangle)
=> ∠CDB + 50° + 65° = 180°
=> ∠CDB = 65°
∠DAB = 65° => ∠ADC= 180° - 65°
=> ∠ADC= 115°
∠ADC= ∠CDB + ∠ADB
=> 115° = 65° + ∠ADB
=> ∠ADB = 50°
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