Question

ABCD is a parallelogram in which angle DAB =65 degrees and angle CBD =50 degrees. find angle CDB and angle ADB​

Answer 1

Answer:

Opposite angles of parallelogram are equal.

∠DAB=∠BCD=75

o

and ∠DBC=60

o

∠BDC+∠DBC+∠BCD=180

o

∠BDC=180

o

−∠DBC−∠BCD=180

o

−75

o

−60

o

=45

o