Question

ABCD is a parallelogram in which angle DAB=70 degree ,Angle DBC=80 degree , calculate angles CDB AND ADB.
Please help!

Answer 1

this is the answer in photo please see it

Answer 2

∠CDB = 30° and ∠ADB = 80°

Step-by-step explanation:

As we know,

ABCD is a ║gm

∠A = ∠C = 70°(opposite angles of a ║gm are equal)

In Δ BCD,

∠DBC + ∠CDB + ∠BCD = 180°

∠CDB = 180° - 80° - 70°

∠CDB = 30°

Since AB║DC & BD is a transversal

∵ ∠ADB = ∠CBD = 80°(alternate angles of a ║gm are equal)

Thus, ∠ADB = 80°

Learn more: calculate the angle

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