ABCD is a parallelogram in which angle DAB=70 degree ,Angle DBC50 degree , calculate angles CDB AND ADB. Please help!
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angle DAB =70
SO,ANGLE DCB=110(PARALLELOGRAM HAVE SUMM OF OPPOSITE ANGLE EQUAL TO 180)
ANGLE DBC=50
THEN THE ANGLE CDB=20 (AS TRIANGLE BCD HAS 180 - 110 - 50)
SO,ANGLE DCB=110(PARALLELOGRAM HAVE SUMM OF OPPOSITE ANGLE EQUAL TO 180)
ANGLE DBC=50
THEN THE ANGLE CDB=20 (AS TRIANGLE BCD HAS 180 - 110 - 50)
chitranshverma2:
and if we extend the line cd angle bde = 160 degree angle bad = angle ade so the angle adb = 60
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This question totally base on diagram if diagram points are right then answer will be right
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