Question

ABCD is a parallelogram in which angle DAB=76° and angle DBC=55°.Calculate angle CDB and angleADB.​

Answer 1

<ADB = <CBD [alternate interior angles of a ||gram]

<ADB = 55° !!!!!

now <ABD = 180° - (<ADB + <A) [angle sum property]

<ABD = 180° - (55° + 76°)

<ABD = 180° - 131°

<ABD = 49°

Also <CDB = <ABD [alternate interior angles of a ||gram]

<CDB = 49° !!!!!

hope it helps you !!!

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Answer 2

Answer:

here's the answer

one thing is that I forgot to give reasons