Question

ABCD is a parallelogram in which angle Dab is equal to 70 degree and Angle CBD is equal to 55 degree find angle dcdb and angle ADB​

Answer 1

Answer:

∠ADB=55°

∠CDB=55°

Step-by-step explanation:

IN //gm ABCD

∠DAB =∠BCD

∴∠BCD =70°

now,

IN ΔBCD,

∠CBD+∠BCD+∠CDB=180°          (ASP)

55°+70°+∠CDB=180°

∴∠CDB=55°

∠CBD=∠ADB            (ALTERNATE INTERIOR ∠LE)

∴∠ADB=55°

Answer 2

the vertically oppositr anhles are made