Question

Abcd is a parallelogram in which bc is produced to e such that ce = bc. Ae intersects cd at f. If ar(dfb) = 3 cm2, find the area of the parallelogram abcd.

Answer 1

Answer:

12cm²

Step-by-step explanation:

ar(ABD)=ar(DBC) {DB is diagonal}----1

ar(DFB)=ar(ADF) {triangles on same base and bw same llLines }----2

NOW, at(EFC) =are(CFB)[because FC is the median of triangleBFC}-----3

In triangelADF and triangleEFC

AD=CE[because BC=CE]

DF=FC[F is mid pt

angleDFA=angleCFE[vertically opposite angle]

we get, arADF=arEFC

arADEarBcf[from3]-----4

Now we get, arDFB=arADF=arBFC=3cm²

Now, arDBC=arDFB+arBFC

arDBC=3+3=6cm²

arABD=6cm²[from1]

arABCD=6+6=12cm²

Answer 2

Step-by-step explanation:

Characteristics of cork are as follow

Cells of cork are dead, compactly arranged and have no intercellular spaces. It forms bark of the tree, which is several layers thick. ... Cork is formed by secondary Lateral Meristem called cork cambium. The mature cork becomes dead and filled with tannin, resin.