abcd is a parallelogram in which dab=60 degrees and dbc=80 degrees ,find abd
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in a parallelogram opposite angles are equal,
let the angles are x,x,y,y
2x + 2y = 360
2(∠DAB) + 2y = 360
120 + 2y = 360
2y = 240
y = 120
y = ∠ABC
y = ∠DBC +∠ABD
y = 80 + ∠ABD
∠ABD = 120 - 80
∠ABD = 40
let the angles are x,x,y,y
2x + 2y = 360
2(∠DAB) + 2y = 360
120 + 2y = 360
2y = 240
y = 120
y = ∠ABC
y = ∠DBC +∠ABD
y = 80 + ∠ABD
∠ABD = 120 - 80
∠ABD = 40
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