ABCD is a parallelogram in which ∠DAB = 70o and ∠CBD = 55o . Find ∠CDB and ∠ADB.
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IN //gm ABCD
∠DAB =∠BCD
∴∠BCD =70°
now,
IN ΔBCD,
∠CBD+∠BCD+∠CDB=180° (ASP)
55°+70°+∠CDB=180°
∴∠CDB=55°
∠CBD=∠ADB (ALTERNATE INTERIOR ∠LE)
∴∠ADB=55°
∠DAB =∠BCD
∴∠BCD =70°
now,
IN ΔBCD,
∠CBD+∠BCD+∠CDB=180° (ASP)
55°+70°+∠CDB=180°
∴∠CDB=55°
∠CBD=∠ADB (ALTERNATE INTERIOR ∠LE)
∴∠ADB=55°
Frostsharmaaayush090:
Its wrong
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