Math, asked by chiragsa, 1 year ago

ABCD is a parallelogram in which ∠DAB = 70o and ∠CBD = 55o . Find ∠CDB and ∠ADB.

Answers

Answered by anaay2002
2
IN //gm ABCD
∠DAB =∠BCD
∴∠BCD =70°
now,
IN ΔBCD,
∠CBD+∠BCD+∠CDB=180°          (ASP)
55°+70°+∠CDB=180°
∴∠CDB=55°

∠CBD=∠ADB            (ALTERNATE INTERIOR ∠LE)
∴∠ADB=55°


Frostsharmaaayush090: Its wrong
anaay2002: oops!!!!
anaay2002:  sorry!
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