Question

ABCD is a parallelogram in which DAB = 75° and DBC = 60° Calculate the measures of CDB and ADB.​

Answer 1

Answer:

In parallelogram ABCD,

∠DAB + ∠ABC = 180°

∠ABC = 180° - 75°

 = 105°

∠ABD = ∠ABC - ∠DBC = 105° - 60° = 45°

In Triangle ABD,

∠ADB = 180 - ∠DAB - ∠ABD = 60°

∠CDB = ∠ABD = 45° (As AB and CD are parallel)

Answer 2

Answer:

In the parallelogram ZDAB+ ZABC = 180° So LABC = 180° - 75° = 105°

So ZABD = <ABC - ZDBC = 105° -60° = 45°

In AABD, ZADB = 180 - ZDAB - ZABD = 60°

As AB and CD are parallel, ZCDB = ZABD = 45°

Step-by-step explanation:

hope this helps u