Math, asked by hraoukoti, 11 months ago

ABCD is a parallelogram in which diagonals AC and BD intersect at o .Pis th midpoint of OA prove that ar(BOP) =1/8 ar(ABCD).

Answers

Answered by abhishekg67007
0

Answer:

hence proved

Step-by-step explanation:

Lets assume ar(BOP)=1/8ar(ABCD)

hence proved

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