ABCD is a parallelogram in which E and F are the mid points of AD and BC resp. Prove that ABllEFllDC.
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ABCD is a parallelogram.
AD II DC (sides of llgm)
AE= ½AD
BF= ½BC
But AD = BC (opp. sides of ||gm)
BF = DE
Again,
AD || BC
=> DE || BF
Now DE || BF and DE = BF
Hence, BFDE is a ||gm.
Therefore, AB ll EF ll DC (proved).
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