Question

ABCD is a parallelogram in which in ∠DAB = 70° and ∠CBD = 50°

Find ∠DCB and ∠ADB.​

Answer 1

Answer:

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Step-by-step explanation:

angle DAB =70

SO,ANGLE DCB=110(PARALLELOGRAM HAVE SUMM OF OPPOSITE ANGLE EQUAL TO 180)

ANGLE DBC=50

THEN THE ANGLE CDB=20 (AS TRIANGLE BCD HAS 180 - 110 - 50)

Answer 2

Answer:

<DCB = 70 &<ADB=50

Step-by-step explanation:

Join diagonal BD in  parallelogram ABCD

Using properties of parallelogram

<CBD = <ADB = 50 (Alternate opposite angles)

similarly <ABD=<BDC=60

now in triangle BDC

use angle sum property

50+60+<DCB=180

<DCB=70