ABCD is a parallelogram in which P and Q are mid-points of opposite sides AB and CD. If AQ intersects DP at S and BQ intersects CP at R, then the total number of parallelograms are:
(a) 2
(b) 5
(c) 6
(d) 4
Answers
The ABCD is frist parallelogram and PQRS is second parallelogram so 2 is right answer
ABCD is a parallelogram in which P and Q are mid-points of opposite sides AB and CD. If AQ intersects DP at S and BQ intersects CP at R, then the total number of parallelograms are 6
Therefore, Option (c) is correct.
Step-by-step explanation:
The figure is attached.
It can be easily proved that
1. APDQ is a parallelogram
2. PQBC is a parallelogram
3. APCQ is a parallelogram
4. BPDQ is a parallelogram
5. PSQR is a parallelogram
6. Also it is given that ABCD is a parallelogram
Therefore, total number of parallelograms are 6
Hope this answer is helpful.
Know More:
Q: ABCD is a parallelogram in which P and Q are mid-points of opposite sides AB and CD (see the below figure). If AQ intersects DP at S and BQ intersects CP at R, show that:
(i) APCQ is a parallelogram.
(ii) DPBQ is a parallelogram.
(iii) PSQR is a parallelogram.
Click Here: https://brainly.in/question/14243885