ABCD is a parallelogram in which P is the midpoint of DC and Q is point on AC such that CQ=1/4AC .such that cq = 1/4 ac if PQ is produce meet BC at r then cr is equal to
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We Know That diagonal of a parallelogram Bisect each other
Construction :- meet line D to B
isliya. CS = 1/2 AC (1)
CQ = 1/4 AC ( Given) (2)
Divided by (2) by (1) Equation
CQ / CS = 1/4 AC /1/2 AC
CQ = 1/2 Cs
Hence Q is mid point Of CS
isliya According to Questions Mid point Theorem in ∆ CSD
PQ//DS
If PQ//DS , we Can Say QR //SB
in ∆ CSB ,Q is mid point Of CS
QR//SB
Applying Converse Of mid point Theorem
so R is mid point of CB
thanks dear friend
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