ABCD is a parallelogram in which P is the midpoint of DC and Q is a point on AC such that CQ = 14 AC (see figure). If PQ produced meets BC at R is the midpoint of BC.
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We know that the diagonals of a parallelogram bisect each other. Therefore, Therefore, according to midpoint theorem in ∆CSD PQ || DS If PQ || DS, we can say that QR || SB In ∆ CSB, Q is midpoint of CS and QR ‖ SB. Applying converse of midpoint theorem , we conclude that R is the midpoint of CB. This completes the proofRead more on Sarthaks.com - https://www.sarthaks.com/134703/abcd-is-a-parallelogram-in-which-p-is-the-midpoint-of-dc-and-q-is-a-point-on-ac-such-that-cq-1-4-ac
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