Question

ABCD is a parallelogram in which perpendiculars BP and DQ are drawn on the diagonal AC from the points B and D respectively.Prove that BPDQ is a parallelograml​

Answer 1

Answer:

It is given that in parallelogram ABCD, BP is perpendicular to AC and DQ is perpendicular to AC.

In ΔADQ and ΔCBP,

AD=CD (Opposite sides of a parallelogram)

∠DAQ=∠BCP and AD∣∣BC,AC (Transversal alternate angles)

∠DQA=∠BPC=90

0

(Given)

⸫ΔADQ=ΔCBP (SAA)

⸫BP=DQ (C.P.C.T)

Hence proved.

it is help for u. follow me and mark as brainlist

Answer 2

Answer:

bhdjdnjzjdjekmdks a few things going with your e

jdu

Step-by-step explanation:

rjjjfjdi the opponent's court in the euro for isidiiejdid a few things that