ABCD is a parallelogram in which x and y are
mid point of its sides DC and AB respectively
prove that Axcy is a parallelogram
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Step-by-step explanation:
in triangle ADX and CBY , we have AD =BC , angle B = angle D and angle DAX = angle angle BCY . ( angle A = angle C
1/2 angle A = 1/2 angle C
angle DAX = angle BCY )
triangle ADX congurent prove triangle CBY.
And therefore, CD - DX = AB - BF.
So, CE = AF
then, AXCY is a parallelogram.
Hence, AE parallel CF.
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