ABCD is a parallelogram in which ZDAB = 70° and ZCBD=55º. Find ZCDB and
ZADB.
jaykrishvara:
ans= ANGLE CDB=55 and angle ADB=55
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Answer:
Z ADB IS 55°
ZCDB=?
SO....
Z A = Z C, SO Z BCD is also 70°
Z D +Z C =180°
Z D =180-70°
Z D =110°
Z ADB +ZBCD=110°
Z BCD = 110° - 55°
Z BCD = 55°
HENCE Z ADB = 55°, Z BCD =55°
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