Math, asked by jaykrishvara, 11 months ago

ABCD is a parallelogram in which ZDAB = 70° and ZCBD=55º. Find ZCDB and
ZADB.


jaykrishvara: ans= ANGLE CDB=55 and angle ADB=55

Answers

Answered by aanchal828564
12

Answer:

Z ADB IS 55°

ZCDB=?

SO....

Z A = Z C, SO Z BCD is also 70°

Z D +Z C =180°

Z D =180-70°

Z D =110°

Z ADB +ZBCD=110°

Z BCD = 110° - 55°

Z BCD = 55°

HENCE Z ADB = 55°, Z BCD =55°

PLZ mark my answer as brainlist


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aanchal828564: thanx
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