ABCD is a parallelogram. LA = 70°, ZDBC = 50°
Find (i) ZADB
(ii) LBDC
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Answer:
∠CDB = 30° and ∠ADB = 80°
Step-by-step explanation:
As we know,
ABCD is a ║gm
∠A = ∠C = 70°(opposite angles of a ║gm are equal)
In Δ BCD,
∠DBC + ∠CDB + ∠BCD = 180°
∠CDB = 180° - 80° - 70°
∠CDB = 30°
Since AB║DC & BD is a transversal
∵ ∠ADB = ∠CBD = 80°(alternate angles of a ║gm are equal)
Thus, ∠ADB = 80°
Step-by-step explanation:
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