ABCD is a parallelogram . M is mid point of CD Prove that EL = 2BL
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see diagram enclosed.
ΔBCM & ΔEDM are similar. And further, MD=CM
=> BC = DE
=> as AD = BC, AE = 2 BC --- (1)
ΔACL & ΔAEL are similar.
=>
EL / BL = AE / BC = 2 from (1)
So EL = 2 BL
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