Math, asked by wonderwomen3000, 6 months ago

ABCD is a parallelogram, M is the mid-point
of BC and AM I BC. Prove that
AD2 = 4(CD2 - AM2)
pls help asap ❣

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Answers

Answered by amitnrw
12

Given :  ABCD is a parallelogram, M is the mid-point  of BC and AM ⊥ BC

To Find : Prove that  AD² = 4(CD²  -  AM²)

Solution:

Applying Pythagoras theorem  as  AM ⊥ BC

BM²  = AB²  - AM²

BM = BC/2  ( as M is mid point )

BC = AD   ∵ opposite sides of parallelogram are equal

=> BM = AD/2

AB = CD  ∵ opposite sides of parallelogram are equal

=> (AD/2)² = CD²  -  AM²

=> AD² / 4  = CD²  -  AM²

=> AD² = 4(CD²  -  AM²)

QED

Hence Proved

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Answered by sarah1272006
1

Answer:

Answer is in the attachment

Step-by-step explanation:

Hope this helps you

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