Question

ABCD is a parallelogram. P and Q are the mid points of the sides AB and BC respectively. If the area of the triangle APQ is 20 square cm, then find the area of the parallelogram ABCD.​

Answer 1

Answer:

area of ABCD = 24

Draw QM and PN and intersect them at O

ar□POQC=14×24=6ar◻POQC=14×24=6

∴AreaPQC=12×6=3∴AreaPQC=12×6=3

PQC=3PQC=3

QMAD=12×24=12QMAD=12×24=12

QAD=12×12=6QAD=12×12=6

arABP=6arABP=6

ar(PQC)+ar(QAD)+ar(ABP)=15ar(PQC)+ar(QAD)+ar(ABP)=15

ar(APQ)=24−15=9cm2ar(APQ)=24−15=9cm2

also

ar(APQ)ar(ABCD)=924=38ar(APQ)ar(ABCD)=924=38

thereforetherefore always it will be 3 : 8

Step-by-step explanation:

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Answer 2

Answer:

3:8 is write answer if yes then please follow me and mark me as brainlist please