Question

ABCD is a parallelogram. P and Q are the mid points of the sides AB and
BC respectively. If the area of the triangle APQ is 20 square cm, then
find the area of the parallelogram ABCD.

Answer 1

Answer:

Answer:

area of ABCD = 24

Draw QM and PN and intersect them at O

ar□POQC=14×24=6ar◻POQC=14×24=6

∴AreaPQC=12×6=3∴AreaPQC=12×6=3

PQC=3PQC=3

QMAD=12×24=12QMAD=12×24=12

QAD=12×12=6QAD=12×12=6

arABP=6arABP=6

ar(PQC)+ar(QAD)+ar(ABP)=15ar(PQC)+ar(QAD)+ar(ABP)=15

ar(APQ)=24−15=9cm2ar(APQ)=24−15=9cm2

also

ar(APQ)ar(ABCD)=924=38ar(APQ)ar(ABCD)=924=38

thereforetherefore always it will be 3 : 8

please mark me brilliant ❤️