Question

ABCD is a parallelogram.P and Q on BC trisects it.Prove that ar(APQ) =ar(DPQ)=1/6ar(ABCD)

Answer 1

hence,proved
it might help you

Answer 2

Answer:hope the answer helps you !!  :

Step-by-step explanation:

Ar(apq).=1/2 *base* height =1/2 *pq*am

Ar(abcd)=b*h= Bc*Am = 3PQ*Am

Ar(abcd)=3*ar(apq)

             =1/6 area abcd =ar(Apq)