Math, asked by Aanyashukla6772, 1 year ago

ABCD is a parallelogram.P and Q on BC trisects it.Prove that ar(APQ) =ar(DPQ)=1/6ar(ABCD)

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Answered by 10DHARMAM

57

hence,proved
it might help you

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Answered by Anonymous

19

Answer:hope the answer helps you !! :

Step-by-step explanation:

Ar(apq).=1/2 *base* height =1/2 *pq*am

Ar(abcd)=b*h= Bc*Am = 3PQ*Am

Ar(abcd)=3*ar(apq)

=1/6 area abcd =ar(Apq)

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