Question

ABCD is a parallelogram .P is a point on BC such that BP:PC =1:2.DP produced meets AB produced at Q . Given area of ∆CPQ=20cm calculate area of triangle CDP

Answer 1

ar(CPQ)=20
DP/PQ=CP/PB=2
ar(CPD)=2*20=40

Answer 2

this is your answer of your question