ABCD is a parallelogram .P is a point on BC such that BP:PC =1:2.DP produced meets AB produced at Q . Given area of ∆CPQ=20cm calculate area of triangle CDP
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Area △CPQ = 20 cm²
Area △BPQ = Area △CPQ / 2 = 10 cm² (△s with same height, base ratio 1:2)
Area △CPD = Area △BPQ * 2² = 40 cm² (similar △s with 2 times sides length)
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