Math, asked by siapandhare3, 1 year ago

ABCD is a parallelogram .P is a point on BC such that BP:PC =1:2.DP produced meets AB produced at Q . Given area of ∆CPQ=20cm calculate area of triangle CDP

Answers

Answered by Shagufta15
107
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Answered by dharmikjethva30
59

Area △CPQ = 20 cm²

Area △BPQ = Area △CPQ / 2 = 10 cm² (△s with same height, base ratio 1:2)

Area △CPD = Area △BPQ * 2² = 40 cm² (similar △s with 2 times sides length)

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