ABCD is a parallelogram. p is any point on CD. if ar (DPA) = 18cm² and ar(APC)=30cm²,find the area of APB
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area (DPA)=15 cm
2
area (APC)=20 cm
2
area (APB)=?
area of △ACD=(15+20) cm
2
=35 cm
2
Now in a parallelogram opp sides are equal.
∴CD=AB
also AB∥CD
Now, we know,
triangles having same base and lie with same ∥ have same area
area of △ABP= area of △ACD
=35 cm.
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