Question

ABCD is a parallelogram P is any point on diagonal AC of parallelogram show that area of AP is equal to area of AP​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

in ΔADP and ΔABP

∠APB= ∠APD (each 90 degree)

AP=AP (common side)

BP=DP (we know that diagonal of a parallelogram bisect each other)

∴ΔADP≅ΔABP By Side Angle Side congruency

and we know that if two triangles are congruent then there area's are also same

area ΔADP=area ΔABP

thanks