Question

ABCD is a parallelogram. Prove that triangle ABD and triangle BDC are similar.​

Answer 1

Answer: abd triangle is always simlar to bdc triangle  

can you share the diagram of that parallelogram

Step-by-step explanation:

Answer 2

Answer:

To prove : - Δ ABD ∼ Δ BDC

Proof :- For the correspondence ABD ↔ CDB between ΔABD and Δ BDC

∠ BAD ≅ ∠ DCB (opposite angles of parallelogram)

∠ABD ≅ ∠CDB (alternate angles )

∠ADB ≅ ∠CDB (alternate angles )

AB = CD (opposite sides of a  parallelogram ABCD )

∴ AB/CD = 1 ..(i)

AB/CD = AD/BC = BD/DB = 1

Hence, for the correspondence, ABD ↔ CDB between ΔABD and ΔBDC

The corresponding angles are congruent and the lengths of its corresponding sides are in proportion.