Question

ABCD is a parallelogram. The diagonals AC and BD intersect each other at O. Prove that ar(∆AOD)=ar(∆BOC).

Answer 1

Step-by-step explanation:

pls mark it as brainleast

Answer 2

Answer:

ABCD is a parallelogram

= AB=CD and AB||CD

= BC = AD and BC||AD

=> Consider that, ΔAOD and ΔBOC

= AD=BC (ABCD is a parallelogram)

= OA=OC (Diagonals bisect eachother)

= OD=OB (Diagonals bisect eachother)

=> By SSS Congruence rule,

= ar(ΔAOD) ≅ ar(ΔBOC)