Math, asked by wwwajithkumarr2141, 9 months ago

ABCD is a parallelogram .The measure of < A of the parallelogram is 65 .Find the measure of the other angles of the parallelogram.

Answers

Answered by Nsega1028
1

Answer:

<A =65

<B =115

<C =65

<D =115

Step-by-step explanation:

it is given that <A is 65.

Since,opposite angles of a parallelogram are equal,

<A = <C = 65

thus, <C = 65

also,

adjacent angles of a parallelogram are supplementary.

so,

<A+<B = 180

--> 65+<B = 180

--> <B = 180-65

thus, <B = 115

by using the same property, we get:

<A+<D = 180

--> 65+<D = 180

--> <D = 180-65

thus,

<D = 115

Therefore, the measure of all the angles are:

<A = 65

<B = 115

<C = 65

<D = 115

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Answered by Sambhavs
12

Answer:

  \sf{\angle{a = 75 \degree}} \\  \rm \blue{then} \\  \\

\bf{\angle{b = 180 \degree  - 75 \degree = 105 \degree}} \\  \rm \blue{then} \\  \\

\tt{\angle{c= 75 \degree}} (opposite \: angle \: are \: equal)\\  \rm \blue{then} \\  \\

\mathcal{\angle{d= 105 \degree}} (opposite \: angle \: are \: equal)\\

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