ABCD is a parallelogram where the base
DC is 6 cm and height is 4 cm. A rhombus
AEFD is drawn on the sides AB and DC
as shown in the figure. AF = 4.5 cm and
DE = 7.5 cm. What is the area of the
parallelogram EBCF?
please answer me it's urjent!!!!
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Answered by
1
Answer:
44.88cm
Step-by-step explanation:
area of AEFD = 16.88 + area of ABCD 6.4=24
Answered by
37
Step-by-step explanation:
base= 6cm
height=4cm
area of parallelogram ABCD = 24cm²
area of rhombus AEFD= diagonal×diagonal ÷2
=4.5×7.5 ÷2
=16.875cm
Now Area of parallelogram EBCF =AREA PARALLELOGRAM ABCD - AREA OF RHOMBUS AEFD
= 24-16.875
=7.125cm²
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