Question

ABCD is a parallelogram where the base
DC is 6 cm and height is 4 cm. A rhombus
AEFD is drawn on the sides AB and DC
as shown in the figure. AF = 4.5 cm and
DE = 7.5 cm. What is the area of the
parallelogram EBCF?
​please answer me it's urjent!!!!

Answer 1

Answer:

44.88cm  

Step-by-step explanation:

area of AEFD = 16.88 +  area of ABCD 6.4=24

Answer 2

Step-by-step explanation:

base= 6cm

height=4cm

area of parallelogram ABCD = 24cm²

area of rhombus AEFD= diagonal×diagonal ÷2

=4.5×7.5 ÷2

=16.875cm

Now Area of parallelogram EBCF =AREA PARALLELOGRAM ABCD - AREA OF RHOMBUS AEFD

= 24-16.875

=7.125cm²