Question

ABCD is a parallelogram where the best
DC is 6 cm and height is 4 cm. A rhombus
AEFD is drawn on the sides AB and DC
as shown in the figure. AF = 45 cm and
DE = 7.5 cm. What is the area of the
parallelogram EBCF?
А
7.5 cm
4 cm
4.5 cm
С​

Answer 1

Answer:

base= 6cm

height=4cm

area of parallelogram ABCD = 24cm²

area of rhombus AEFD= diagonal×diagonal ÷2

=4.5×7.5 ÷2

=16.875cm

Now Area of parallelogram EBCF =AREA PARALLELOGRAM ABCD - AREA OF RHOMBUS AEFD

= 24-16.875

=7.125cm²

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION