Question

ABCD is a parallelogram whose diagonals AC and BD intersect each other at
right angles. If AC = 16cm and BD = 12cm, find AB

Answer 1

Answer:

8cm

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Answer 2

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In parallelogram ABCD, AC and BD intersect at right angles. If AC = 16 cm and BD = 12 cm, then AO = OC and OB = OD where O is the point of intersection of AC and BD. O must be the mid point of AC and BD. By Pythagoras theorem, AB = [AO^2+BO^2]^0.5 = [8^2+6^2]^0.5 = 10 cm.

In parallelogram ABCD, AC and BD intersect at right angles. If AC = 16 cm and BD = 12 cm, then AO = OC and OB = OD where O is the point of intersection of AC and BD. O must be the mid point of AC and BD. By Pythagoras theorem, AB = [AO^2+BO^2]^0.5 = [8^2+6^2]^0.5 = 10 cm.In fact all sides will be 10 cm and ABCD will be a rhombus.