ABCD is a parallelogram whose diagonals intersect each other at right angles.if the length of the diagonals is 6 cm and 8 cm. find the length of all sides of parallelogram.
Answers
Answered by
314
half of 1st diagonal=3cm
half of 2nd diagonal=4cm
one side of ∥gm=√[3²+4²]=5cm
other side of ∥gm also=5cm
so it is square with each side = 5cm
for doubts comment
MARK ANSWER AS BRAINLIEST
half of 2nd diagonal=4cm
one side of ∥gm=√[3²+4²]=5cm
other side of ∥gm also=5cm
so it is square with each side = 5cm
for doubts comment
MARK ANSWER AS BRAINLIEST
Answered by
593
ABCD is a parallelogram whose diagonals intersect each other at O with 90°.
so it's a rhombus as diagonals of rhombus interest each other at right angles.
diagonal1 (AC) = 6cm
diagonal 2(BD) = 8cm
OD = OB = 3cm each
OA = OC = 4cm each
Let, us take triangle AOB
it is a right angled triangle
=> (OA)² + (OB)² = (AB)²
=> (4)² + (3)² = (AB)²
=> 16 + 9 = (AB)²
=> 25 = (AB)²
=> = AB
=> 5 = AB
So, AB = 5cm
AB = BC = CD = AD (all sides of rhombus are equal)
Each side of the parallelogram ABCD is 5cm.
so it's a rhombus as diagonals of rhombus interest each other at right angles.
diagonal1 (AC) = 6cm
diagonal 2(BD) = 8cm
OD = OB = 3cm each
OA = OC = 4cm each
Let, us take triangle AOB
it is a right angled triangle
=> (OA)² + (OB)² = (AB)²
=> (4)² + (3)² = (AB)²
=> 16 + 9 = (AB)²
=> 25 = (AB)²
=> = AB
=> 5 = AB
So, AB = 5cm
AB = BC = CD = AD (all sides of rhombus are equal)
Each side of the parallelogram ABCD is 5cm.
Attachments:
Similar questions